A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.
The quotient to describe the rate of change in the squirrel's height above the ground is the distance traveled divided by the time taken.
The distance traveled is 100 - 45 = 55 feet.
The time taken is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55/5.25 ≈ 10.48 feet per second.
negative or positive?
The rate of change in the squirrel's height above the ground is negative because the squirrel is moving downwards from its perch to the stored acorns.
To interpret the quotient that describes the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took.
The squirrel starts at a height of 100 feet above the ground and moves down to a height of 45 feet above the ground. The change in height is 100 - 45 = 55 feet.
The time it took for the squirrel to make this change in height is 5.25 seconds.
We can now calculate the rate of change by dividing the change in height by the time taken:
Rate of change = Change in height / Time taken
Rate of change = 55 feet / 5.25 seconds
Rate of change ≈ 10.48 feet/second (rounded to the nearest hundredth)
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet per second.
To find the rate of change in the squirrel's height above the ground, we need to determine the vertical distance the squirrel descends and divide it by the time it takes.
The squirrel starts at a height of 100 feet above the ground and moves down to a hole that is 45 feet from the ground. The vertical distance traveled by the squirrel is 100 - 45 = 55 feet.
The time it takes for the squirrel to complete this descent is given as 5.25 seconds.
To find the rate of change, divide the vertical distance traveled by the time taken:
Rate of change = Vertical distance / Time
Rate of change = 55 feet / 5.25 seconds
Calculating this quotient, we find:
Rate of change = 10.47619 feet/second
Rounded to the nearest hundredth, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second.