A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth. (1 point)
O Tre suetent that describes the rate of change in the squirels height above the ground is 10.48
• thre suetent that describes the rate of change in the squirels height above the ground is 19.05
• The quotient that describes the rate of change in the squirrel's height above the ground is
-19.05 feet/second.
O The quotient that describes the rate of change in the squirrel's height above the ground is
-10.48 feet/second.
The correct interpretation is: The quotient that describes the rate of change in the squirrel's height above the ground is -19.05 feet/second.
The correct answer is: The quotient that describes the rate of change in the squirrel's height above the ground is -19.05 feet/second.
To find the rate of change in the squirrel's height above the ground, we need to calculate the change in height and the time it took for that change to occur.
The squirrel starts on a perch 100 feet above the ground and moves to its stored acorns in a hole that is 45 feet from the ground. The total change in height is given by 100 feet - 45 feet = 55 feet.
The time it took for the squirrel to move from the perch to the acorns is given as 5.25 seconds.
To find the rate of change, we divide the change in height by the time taken:
Rate of change = Change in height / Time taken
Rate of change = 55 feet / 5.25 seconds
Calculating this, we find that the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second.
Therefore, the correct answer is: The quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.