A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth.
(1 point)
The quotient can be interpreted as the rate of change in the squirrel's height above the ground. To find the rate of change, we divide the change in height by the time taken.
The squirrel starts at a height of 100 feet above the ground and moves down to a height of 45 feet above the ground. The change in height is 100 - 45 = 55 feet.
The time taken is 5.25 seconds.
The rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds = 10.48 feet/second.
Therefore, the rate of change is approximately 10.48 feet/second.
To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time taken.
Given that the squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns 45 feet from the ground, the change in height is 100 - 45 = 55 feet.
The time taken by the squirrel to move down is given as 5.25 seconds.
The rate of change is then calculated as the change in height divided by the time taken:
Rate of change = Change in height / Time taken
= 55 feet / 5.25 seconds
≈ 10.48 feet/second
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second to the nearest hundredth.
To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took.
The squirrel starts on a perch 100 feet above the ground and moves down to the stored acorns, which are 45 feet from the ground. The change in height is calculated by subtracting the final height from the initial height:
Change in height = 100 ft - 45 ft = 55 ft
The squirrel took 5.25 seconds to make this descent.
Now, to calculate the rate of change, we divide the change in height by the time:
Rate of change = Change in height / Time = 55 ft / 5.25 s
To calculate this, divide 55 by 5.25 using a calculator or by performing long division:
(55 / 5.25) ≈ 10.48 ft/s
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet per second.