A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.
The correct interpretation of the quotient is:
The quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
To interpret the quotient, we need to calculate the rate of change in the squirrel's height above the ground.
First, we'll find the difference in height between the perch and the stored acorns: 100 feet - 45 feet = 55 feet.
Next, we divide the difference in height by the time it took the squirrel to descend: 55 feet / 5.25 seconds = 10.48 feet/second.
Therefore, the correct answer is:
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.