A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.
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To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took to make that change.
The squirrel's starting height is 100 feet and it moves down to a height of 45 feet. Therefore, the change in height is 100 - 45 = 55 feet.
The time it took for the squirrel to make that change is 5.25 seconds.
Now, we can calculate the rate of change by dividing the change in height by the time: 55 feet / 5.25 seconds ≈ 10.48 feet per second.
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet per second.
To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it takes to make that change.
The squirrel starts on a perch 100 feet above the ground and moves down to the stored acorns 45 feet above the ground. Therefore, the change in height is 100 - 45 = 55 feet.
The squirrel takes 5.25 seconds to make this change in height.
To find the rate of change, we divide the change in height by the time taken:
Rate of change = change in height / time taken
Rate of change = 55 feet / 5.25 seconds
Calculating this, we get:
Rate of change ≈ 10.48 feet/second
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second.