escrow has stored it’s acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground the squirrel moves from the perch down to its store or acorns in 5.2 5 seconds interpret the quotient to describe the rate change in the squirrels height above the ground give your answer to the nearest hundred.
To find the rate change in the squirrel's height above the ground, we need to divide the change in height by the time it took for that change to occur.
The squirrel starts on a perch 100 feet above the ground and moves down to its store of acorns, which is 45 feet from the ground. The change in height is 100 - 45 = 55 feet.
The time it took for the squirrel to make this change is given as 5.2 seconds.
To find the rate change, we divide the change in height by the time: 55 / 5.2 = 10.577.
Rounding to the nearest hundred, we can interpret the quotient as 11. Therefore, the rate change in the squirrel's height above the ground is approximately 11 feet per second.
To find the rate change in the squirrel's height above the ground, we need to calculate the difference in height between the perch and the acorn hole and divide it by the time it takes for the squirrel to move from the perch to its acorn store.
Given:
Height of the perch = 100 feet
Height of the acorn hole = 45 feet
Time taken to reach the acorn hole = 5.25 seconds
Now, let's calculate the difference in height:
100 feet (perch height) - 45 feet (acorn hole height) = 55 feet
Next, we divide the height difference by the time taken:
55 feet / 5.25 seconds ≈ 10.48 feet per second
Therefore, the quotient represents the rate change in the squirrel's height above the ground, which is approximately 10.48 feet per second (rounded to the nearest hundred).