Philip is sorting acorns he collected. He has 92 acorns: 66 still have their tops, 26 do not. Philip wants to sort the acorns into groups with the same number of acorns, including some with and without tops. He wants each group to have an equal number of acorns with tops and an equal number of acorns without tops. Which answer best shows how Philip can represent how he should sort the acorns?(1 point)
Responses
6(11+4)
6 left parenthesis 11 plus 4 right parenthesis
2(33+13)
2 left parenthesis 33 plus 13 right parenthesis
1(66+26)
1 left parenthesis 66 plus 26 right parenthesis
24(3+1)
24 left parenthesis 3 plus 1 right parenthesis
wrong 1(66+26)
BRO MY THING IS A WEEK PAST DUE PLEASE ASAP ANSWERS PLEASE!!!!
This doesn't help me
still no answers -_-
To solve this problem, we need to find a combination of acorns with tops and acorns without tops that will divide evenly into groups. Let's go through the options one by one:
1. 6(11+4): This option suggests sorting the acorns into groups of size 11+4, which is 15. However, 92 is not divisible by 15, so this option is not correct.
2. 2(33+13): This option suggests sorting the acorns into groups of size 33+13, which is 46. However, 92 is not divisible by 46, so this option is not correct.
3. 1(66+26): This option suggests sorting the acorns into groups of size 66+26, which is 92. This means that each group will have 66 acorns with tops and 26 acorns without tops. Since 92 is divisible by 92, this option is a valid solution.
4. 24(3+1): This option suggests sorting the acorns into groups of size 3+1, which is 4. However, 92 is not divisible by 4, so this option is not correct.
The correct answer is 1(66+26), meaning that Philip should sort the acorns into groups with 66 acorns with tops and 26 acorns without tops.