Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the area of the rectangle in square feet.
First, we need to find the length and width of the rectangle. The length is the distance between points A and D, which is 6 - 1 = 5 feet.
The width is the distance between points A and B, which is -2 - (-5) = 3 feet.
Therefore, the area of the rectangle is:
Area = length x width
Area = 5 feet x 3 feet
Area = 15 square feet
Answer: \boxed{15}.