A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?
We can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
F = m x a
In this case, the mass of the softball is 0.2 kg and the acceleration is 8 m/s^2.
F = 0.2 kg x 8 m/s^2
F = 1.6 Newtons
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).
Given:
Mass of the ball (m) = 0.2 kilograms
Acceleration of the ball (a) = 8 meters per second squared
Using the formula F = m * a, we can calculate the force:
F = 0.2 kg * 8 m/s^2
F = 1.6 Newtons
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula for this equation is:
Force (F) = Mass (m) × Acceleration (a)
Given:
Mass (m) = 0.2 kilograms
Acceleration (a) = 8 meters per second squared
We can substitute these values into the formula and calculate the force:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 Newtons
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons.