Bowl a 45 white balls 55 red balls
Bowl b 60 white balls 40 red balls
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
In Bowl A, the probability of selecting a white ball is 45/100 = 0.45 and the probability of selecting a red ball is 55/100 = 0.55.
In Bowl B, the probability of selecting a white ball is 60/100 = 0.6 and the probability of selecting a red ball is 40/100 = 0.4.
Since Clark repeatedly selected a ball from both bowls, the expected number of white balls selected from Bowl B can be calculated as:
Expected number of white balls = 0.6 * Number of balls in Bowl B = 0.6 * 500 = 300 white balls
Similarly, the expected number of red balls selected from Bowl B can be calculated as:
Expected number of red balls = 0.4 * Number of balls in Bowl B = 0.4 * 500 = 200 red balls
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is:
300 white balls - 200 red balls = 100 balls
The estimated difference in the expected number of white and red balls in Bowl B is 100 balls.