Simon result
Bowl A white balls 5, red balls 15
Bowl B white balls 16. Red balls 4
Clark result
Bowl A white balls 45. Red balls 55
Bowl B white balls 60. Red balls 40
Bowls A and B contain a number of white balls. Whose results will give you a better indication about yhe proportion of white and red balls in each bowl?
Clark's results will give a better indication about the proportion of white and red balls in each bowl, as he has a larger sample size than Simon. With a larger sample size, the results are likely to be more accurate and representative of the overall proportion. Additionally, Clark's results show a higher number of white balls in Bowl A and B, indicating that these bowls may have a higher proportion of white balls compared to red balls.
To determine which results give a better indication of the proportion of white and red balls in each bowl, we can compare the proportions of white and red balls in the results of Simon and Clark.
For Simon's results:
- Bowl A has 5 white balls and 15 red balls.
- Bowl B has 16 white balls and 4 red balls.
Proportion of white balls in Bowl A for Simon: 5/20 = 0.25 (or 25%)
Proportion of white balls in Bowl B for Simon: 16/20 = 0.8 (or 80%)
Now let's look at Clark's results:
- Bowl A has 45 white balls and 55 red balls.
- Bowl B has 60 white balls and 40 red balls.
Proportion of white balls in Bowl A for Clark: 45/100 = 0.45 (or 45%)
Proportion of white balls in Bowl B for Clark: 60/100 = 0.6 (or 60%)
Comparing the proportions, we can see that Clark's results will give a better indication of the proportion of white and red balls in each bowl. This is because Clark's sample size is larger (100 balls) compared to Simon's (20 balls), providing a more accurate representation of the actual proportions in the bowls.