Find the perimeter of rectangle abcd, with vertices A(1,7),B(4,7),C(4,-4) andD(1,-4)
To find the perimeter of a rectangle, we need to add up the lengths of all four sides.
Side AB: √((4-1)^2 + (7-7)^2) = 3 units
Side BC: √((4-4)^2 + (-4-7)^2) = 11 units
Side CD: √((1-4)^2 + (-4+4)^2) = 3 units
Side DA: √((1-1)^2 + (7+4)^2) = 11 units
Adding up all four sides:
Perimeter AB + BC + CD + DA = 3 + 11 + 3 + 11 = 28 units
Therefore, the perimeter of rectangle ABCD is 28 units.