Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

Question

Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

A) 1.68
B) 1.95
C) 0.59
D) 0.75

Answer 1

To use Snell's law, which states n1sin(theta1) = n2sin(theta2), we first need to determine the incident angle in the glass. This can be done using the information given:

n1 = 1.00 (index of refraction for air)
theta1 = 60 degrees
theta2 = 31 degrees

Now we can plug these values into Snell's law:

1.00*sin(60 degrees) = n2*sin(31 degrees)

0.866 = n2*sin(31 degrees)

To solve for n2, we divide both sides by sin(31 degrees):

n2 = 0.866 / sin(31 degrees)
n2 ≈ 1.68

Therefore, the index of refraction of the glass is approximately 1.68.

So, the correct answer is:

A) 1.68

Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

To use Snell's law, which states n1*sin(theta1) = n2*sin(theta2), we first need to determine the incident angle in the glass. This can be done using the information given:

To use Snell's law, which states n1sin(theta1) = n2sin(theta2), we first need to determine the incident angle in the glass. This can be done using the information given: