Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

Question

Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

Responses

a) 1.68

b) 0.75

c) 0.59

d) 1.95

Answer 1

1.It is upside down and smaller than the object.

2.They bounce back.
3.Magnified
4.They bend.
5.1.68
trust

Answer 2

We know that Snell's law is given by:

n1sinθ1 = n2sinθ2

where n1 is the index of refraction of the first medium (air), θ1 is the incident angle, n2 is the index of refraction of the second medium (glass), and θ2 is the angle of refraction.

We can use this equation to find n2:

n2 = n1sinθ1/sinθ2

Substituting the given values:

n2 = 1.00(sin60)/sin31

n2 = 1.68

Therefore, the index of refraction of the glass is 1.68.

Answer: (a) 1.68

Answer 3

100% is correct

Answer 4

Well, well, well! Let's put on our clown glasses and solve this! 🤡

Snell's law states that the ratio of the sin of the incident angle to the sin of the refracted angle is equal to the ratio of the indices of refraction of the two mediums.

So, we have sin(60) / sin(31) = n_glass / n_air

Since the index of refraction for air is 1.00, we can rearrange the equation to find n_glass.

n_glass = sin(60) / sin(31) * 1.00

After performing the calculations, the value of n_glass is approximately 1.95.

So, the correct answer is d) 1.95.

Don't worry, folks, I won't make your head spin like that glass did to the light ray! 🌈

Answer 5

To use Snell's law to determine the index of refraction of the glass, we need to use the formula:

n1*sin(theta1) = n2*sin(theta2)

where n1 and n2 are the indices of refraction of the two media and theta1 and theta2 are the angles of incidence and refraction measured from the normal.

In this question, the light ray is passing from air to glass, so n1 is the index of refraction for air (which is 1.00). The incident angle is 60 degrees, and the angle of refraction in the glass is 31 degrees.

Using the formula, we can plug in the values:

1.00*sin(60) = n2*sin(31)

Solving for n2, we get:

n2 = (1.00*sin(60)) / sin(31)

n2 ≈ 1.68

Therefore, the index of refraction of the glass sample is approximately 1.68.

So, the correct answer is:

a) 1.68