Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)
a. 0.75
b. 0.59
c. 1.95
d. 1.68
To solve this problem, we can use Snell's Law which states:
n1*sin(theta1) = n2*sin(theta2)
where n1 is the index of refraction of the first medium, theta1 is the incident angle, n2 is the index of refraction of the second medium, and theta2 is the refracted angle.
Given:
n1 = 1.00 (index of refraction of air)
theta1 = 60 degrees
theta2 = 31 degrees
Let's plug in the values:
1.00*sin(60) = n2*sin(31)
Solving for n2:
n2 = (1.00*sin(60)) / sin(31)
n2 = 0.75
Therefore, the index of refraction of the sample of glass is 0.75, so the correct answer is:
a. 0.75