Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)
Responses
1.68
0.59
1.95
0.75
To solve for the index of refraction of the glass, we can use Snell's law which is given as:
n1 * sin(theta1) = n2 * sin(theta2)
Where:
n1 = index of refraction of the medium the light ray is traveling in (air) = 1.00
theta1 = incident angle = 60 degrees
n2 = index of refraction of the glass (what we want to find)
theta2 = angle of refraction = 31 degrees
Plugging in the values:
1.00 * sin(60) = n2 * sin(31)
1.00 * 0.866 = n2 * 0.515
n2 = 0.866 / 0.515
n2 = 1.68
Therefore, the index of refraction of the glass is 1.68.
So, the correct response is 1.68.