Find the perimeter of rectangle ABCD, with vertices A(- 8, 3) B(- 1, 3) C(- 1,- 6) and D(- 8, - 6) (1 point)
63 units
30 units
36 units
32 units
The perimeter of a rectangle is calculated by adding the lengths of all four sides.
To find the length of each side, we can use the distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)
Side AB: √((-1 + 8)^2 + (3 - 3)^2) = √(7^2) = 7 units
Side BC: √((-1 + 1)^2 + (-6 - 3)^2) = √((-9)^2) = 9 units
Side CD: √((-8 + 1)^2 + (-6 + 6)^2) = √(-7^2) = 7 units
Side DA: √((-8 + 8)^2 + (-6 - 3)^2) = √((-9)^2) = 9 units
Now, add the lengths of all four sides:
Perimeter = 7 + 9 + 7 + 9 = 32 units
Therefore, the perimeter of rectangle ABCD is 32 units.
The correct answer is:
32 units