A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105 gallons of water. How many tetras can it house? Write the answer in scientific notation.(1 point)$$
The number of tetras that can be housed in the aquarium can be calculated by dividing the total gallons of water in the aquarium by the gallons of water needed for each tetra:
\( \frac{1 \times 10^5}{1.25} = 8 \times 10^4 \)
Therefore, the aquarium can house 8 x 10^4, or 80,000, neon tetras.