What is the strength of an electric field in which a charged particle of 3.0 × 10−9 C is 0.05 m from the test charge?(1 point)
Responses
60 N/C
539 N/C
3.6 × 103 N/C
1.1 × 104 N/C
The strength of an electric field produced by a charged particle can be calculated using the formula:
Electric Field = Coulomb's constant * Charge of the particle / Distance^2
Given:
Charge of the particle = 3.0 × 10^(-9) C
Distance from the test charge = 0.05 m
Plugging in the values into the formula:
Electric Field = (9 × 10^9 N m^2/C^2) * (3.0 × 10^(-9) C) / (0.05 m)^2
Electric Field = (9 × 10^9 N m^2/C^2) * (3.0 × 10^(-9) C) / (0.0025 m^2)
Electric Field = (9 × 3.0 × 10) / (0.0025) N/C
Electric Field = 27 × 10^9 / 0.0025 N/C
Electric Field = 27 × 10^9 × 400 N/C
Electric Field = 1.08 × 10^13 N/C
Therefore, the strength of the electric field is approximately 1.1 × 10^4 N/C.