What is the strength of an electric field in which a charged particle of 3.0*10^-9 C is 0.05m from the test charge
A) 1.1*10^4 N/C
B) 3.6*10^3 N/C
C) 60 N/C
D) 539 N/C
The strength of an electric field can be calculated using the formula:
E = k * (Q / r^2)
Where:
- E is the strength of the electric field
- k is the Coulomb's constant (approximately 9 × 10^9 Nm^2/C^2)
- Q is the charge of the particle
- r is the distance from the test charge to the particle
Plugging in the given values:
E = (9 × 10^9 Nm^2/C^2) * (3.0 × 10^-9 C) / (0.05m)^2
E = (9 × 10^9 Nm^2/C^2) * (3.0 × 10^-9 C) / (0.0025m^2)
E = (9 × 3.0 × 10) N/C
E = 27 × 10 N/C
E = 270 N/C
Therefore, the strength of the electric field is 270 N/C. None of the given answer options match this value, so none of the options are correct.