What is the strength of an electric field in which a charged particle of 3.0*10^-9 C is 0.05 m from the test charge
A) 1.1*10^4 N/C
B) 3.6*10^3 N/C
C) 60 N/C
D) 539 N/C
The strength of an electric field can be calculated using the formula:
E = k * Q / r^2
Where E is the strength of the electric field, k is the electrostatic constant (9.0 * 10^9 N*m^2/C^2), Q is the charge of the particle (.03 C), and r is the distance from the charged particle to the test charge (.05 m).
Plugging in the given values:
E = (9.0 * 10^9 N*m^2/C^2) * (.03 C) / (.05 m)^2
E = (2.7 * 10^8 N*m^2/C) / .0025 m^2
E = 1.08 * 10^11 N/C
So the strength of the electric field is approximately 1.08 * 10^11 N/C.
None of the given answer choices match this value, so the correct answer is not provided.