What is the strength of an electric field in which a charged particle of 3.0*10^-9 C is 0.05m from the test charge?
A) 1.1*10^4 N/C
B) 3.6*10^3 N/C
C) 60 N/C
D) 539 N/C
The strength of an electric field is given by the equation:
Electric field strength (E) = Force (F) / Charge (q)
The force between two charges is given by Coulomb's law:
Force (F) = (k * |q1 * q2|) / r^2
Where k is the electrostatic constant (9.0 * 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
In this case, the charge q1 is the test charge (the charged particle) and q2 is the charge creating the field. The test charge is 3.0 * 10^-9 C and the distance is 0.05 m.
Plugging these values into the equation:
Force (F) = (9.0 * 10^9 N m^2/C^2 * |3.0 * 10^-9 C * q2|) / (0.05 m)^2
We don't have the value of q2, so we can't solve for the force at this point.
Therefore, we cannot determine the strength of the electric field without additional information.