A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.(1 point)
Responses
6
6
9
9
18
18
3
The rabbit will need to have 9 baby bunnies.
To find this, we can divide the total number of carrots (90) by the number of carrots each bunny will receive. Similarly, we can divide the total number of lettuce leaves (72) by the number of leaves each bunny will receive.
If each bunny receives the same number of carrots and lettuce leaves, we can divide the total number of carrots and lettuce leaves by the same number.
Let's use x as the number of carrots and lettuce leaves each bunny will receive.
90 carrots / x carrots = 72 leaves / x leaves
Simplifying this equation, we get:
90 / x = 72 / x
Since the equation is equal, we can omit the denominators and solve for x:
90 = 72
This simplifies to:
9 = 72
Since this equation is not true, we need to find another value for x.
By trial and error, we can find that if x = 9, the equation holds true:
90 carrots / 9 carrots = 72 leaves / 9 leaves
10 bunnies = 8 bunnies
Since both sides of the equation are equal, x = 9 is a valid solution.
Therefore, the rabbit must have 9 baby bunnies.