A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches
Same type of problem as the one above this one, and
once again the Robot Tutor messes up and get the wrong answer:
correct solution:
The HCF of 90 and 72 is 18.
So the maximum number of lunch bags would be 18
each with 5 carrots and 4 leaves of lettuce
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uhh i think the answer should be 18
sorry bought GPT 3.5 you are incorrect
To find out how many baby bunnies there must be, we need to determine the greatest common divisor (GCD) of 90 and 72. The GCD represents the largest number that can evenly divide both 90 and 72 without leaving a remainder.
To find the GCD, we can use the Euclidean algorithm:
1. Start by dividing the larger number (90) by the smaller number (72).
90 ÷ 72 = 1 remainder 18
2. Next, divide the previous divisor (72) by the remainder (18).
72 ÷ 18 = 4 remainder 0
Since the remainder is 0, we have found the GCD. In this case, the GCD of 90 and 72 is 18.
Therefore, to pack lunches with no extra vegetables, the rabbit must have 18 baby bunnies. Each bunny will receive 90/18 = 5 carrots and 72/18 = 4 leaves of lettuce.