A rabbit is packing lunches for his children. He has 120 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.
*
120
72
12
24
To find out how many baby bunnies there are, we need to find the common factor of 120 and 72.
By listing the factors of 120, we have:
1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120.
By listing the factors of 72, we have:
1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.
The common factors of 120 and 72 are 2, 3, 4, 6, 8, 12, and 24.
Therefore, he must have 24 baby bunnies in order to have no extra vegetables after packing the lunches.
To determine how many baby bunnies the rabbit must have, we need to find the common factor of 120 and 72.
Let's start by finding the factors of both numbers:
Factors of 120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120
Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
From the factors listed above, we can see that the common factor of 120 and 72 is 24.
Therefore, the rabbit must have 24 baby bunnies.