A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.(1 point)
Responses
9
9
6
6
3
3
18
18
To find the number of baby bunnies, we need to find the greatest common factor of 90 and 72. The greatest common factor of 90 and 72 is 18. So, the rabbit must have 18 baby bunnies.
To find out how many baby bunnies the rabbit must have, we need to determine the greatest common divisor (GCD) of 90 and 72. The GCD represents the largest number that divides both 90 and 72 evenly.
Using the prime factorization method, we can find the GCD as follows:
90 = 2 * 3^2 * 5
72 = 2^3 * 3^2
Now, we'll count the common factors and multiply them together:
Common factors:
- 2^1
- 3^2
To find the GCD, we multiply the common factors:
GCD = 2^1 * 3^2 = 2 * 9 = 18
Therefore, the rabbit must have 18 baby bunnies in order to distribute the carrots and lettuce evenly.