Philip is sorting acorns he collected. He has 92 acorns: 66 still have their tops, 26 do not. Philip wants to sort the acorns into groups with the same number of acorns, including some with and without tops. He wants each group to have an equal number of acorns with tops and an equal number of acorns without tops. Which answer best shows how Philip can represent how he should sort the acorns?(1 point) Responses 24(3+1) 24 left parenthesis 3 plus 1 right parenthesis 2(33+13) 2 left parenthesis 33 plus 13 right parenthesis 1(66+26) 1 left parenthesis 66 plus 26 right parenthesis 6(11+4)
The Distributive Property Quick Check 2 of 52 of 5 Items Question Mei is playing a game with numbers. She decides to rewrite the number 78 using the Distributive Property. Which answer is a correct way to rewrite 78 using the Distributive Property of Multiplication over Addition?(1 point) Responses 78=18+60=(6×3)+(6×10)=6(3+10) 78 equals 18 plus 60 equals left parenthesis 6 times 3 right parenthesis plus left parenthesis 6 times 10 right parenthesis equals 6 left parenthesis 3 plus 10 right parenthesis 78=24+54=(6×4)+(6×9)=6(4×9) 78 equals 24 plus 54 equals left parenthesis 6 times 4 right parenthesis plus left parenthesis 6 times 9 right parenthesis equals 6 left parenthesis 4 times 9 right parenthesis 78=11+67=(1×11)+(1×67)=1(11×67) 78 equals 11 plus 67 equals left parenthesis 1 times 11 right parenthesis plus left parenthesis 1 times 67 right parenthesis equals 1 left parenthesis 11 times 67 right parenthesis 78=22+56=(2×11)+(2×28)=2(11×28)
78=6(3+10)
Sven is making a school supply display. Sven has 52 notebooks and 42 binders. Sven wants to group the supplies in the display so that there are an equal number of supplies in each group. If we know that Sven puts the same number of notebooks and the same number of binders into each group, how many groups did he display and how many of each item went into each group? Represent your answer using the Distributive Property of Multiplication over Addition.(1 point) Responses Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21). Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 times 21 right parenthesis . Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52+42). Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 plus 42 right parenthesis . Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21). Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis . Sven made 1 group. He put all
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21).
Given the sum 100=64+36, rewrite 64+36 using their GCF and multiplication.(1 point) Responses 4(16×9) 4 left parenthesis 16 times 19 right parenthesis 4(16+9) 4 left parenthesis 16 plus 9 right parenthesis 2(32+18) 2 left parenthesis 32 plus 18 right parenthesis 1(64+36)
2(32+18)
Given the sum 18=6+12, rewrite 6+12 using their GCF and multiplication. (1 point) Responses 3(2+4) 3 times open paren 2 plus 4 close paren 6(1+2) 6 times open paren 1 plus 2 close paren 6(1×2) 6 times open paren 1 times 2 close paren 1(6+12)
