A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point? (1 point)
The climber has climbed a total of 182 + 208 = <<182+208=390>>390 ft.
To return to his original starting point, the climber needs to descend another 380 ft.
Therefore, the climber needs to descend a total of 380 - 235 = <<380-235=145>>145 ft to return to his original starting point. Answer: \boxed{145}.
answer choices
155
78
535
235
The correct answer is 155.
To find out how much the climber needs to descend to return to his original starting point, we need to calculate the total elevation change.
First, let's calculate the total elevation the climber climbed. At the first rest stop, he climbed 182 ft. At the second rest stop, he climbed another 208 ft. So, the total elevation climb is 182 ft + 208 ft = 390 ft.
Now, let's calculate the total elevation change. The climber started at an elevation of 380 ft above sea level and climbed 390 ft, so the total elevation change is 380 ft + 390 ft = 770 ft.
However, since the climber starts descending to return to his original starting point, we need to subtract the descent from the total elevation change. The climber descends 235 ft, so we subtract 235 ft from 770 ft, resulting in 770 ft - 235 ft = 535 ft.
Therefore, the climber needs to descend 535 ft to return to his original starting point.