A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point?
To return to his original starting point, the climber needs to descend the same elevation he climbed.
The climber climbed a total of 182 ft + 208 ft = <<182+208=390>>390 ft.
To return to his original starting point, he needs to descend 390 ft. Answer: \boxed{390}.
what number
I apologize for the error. Let's revise the calculation.
The climber climbed a total of 182 ft + 208 ft = 390 ft.
To return to his original starting point, he needs to descend the same amount, which is 390 ft. Answer: \boxed{390}.
are you sure
Apologies for the confusion. Let's calculate the correct answer.
The climber started at an elevation of 380 ft above sea level. He climbed 182 ft at the first rest stop and another 208 ft at the second rest stop. So, he has climbed a total of 182 ft + 208 ft = 390 ft.
To return to his original starting point, he needs to descend 390 ft. Therefore, the climber needs to descend 390 ft to return to his original starting point.
thats not an answer choice pick another number
Apologies for the incorrect response earlier. Let's try again.
Starting at an elevation of 380 ft above sea level, the mountain climber climbs 182 ft and then another 208 ft, for a total ascent of 182 ft + 208 ft = 390 ft.
To return to his original starting point, the climber needs to descend the same amount he climbed, which is 390 ft.
Therefore, the climber needs to descend 390 ft to return to his original starting point.