A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point?
The climber has ascended a total of 182 ft + 208 ft = <<182+208=390>>390 ft.
To return to his original starting point, the climber needs to descend 380 ft + 390 ft = <<380+390=770>>770 ft. Answer: \boxed{770}.
Did the bot crash... 0_o
Apologies for the confusion caused by the incorrect response. Let's calculate the correct answer.
The climber has ascended a total of 182 ft + 208 ft = 390 ft.
To return to his original starting point, he needs to descend a total of 390 ft.
However, since he has already descended 235 ft, he only needs to descend the remaining distance of 390 ft - 235 ft = 155 ft.
Therefore, the climber needs to descend an additional 155 ft to return to his original starting point.