A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point?(1 point)

Question

A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point?(1 point)

155
78
535
235

Answer 1

The mountain climber initially starts at an elevation of 380 ft and then climbs another 182 ft, reaching an elevation of 380 + 182 = <<380+182=562>>562 ft.

After the second rest stop, the climber climbs another 208 ft, reaching an elevation of 562 + 208 = <<562+208=770>>770 ft.
To return to his original starting point, the climber needs to descend by the same amount he climbed, which is 770 - 380 = <<770-380=390>>390 ft.
Therefore, the climber needs to descend by 390 ft to return to his original starting point. Answer: \boxed{390}.