A mountain climber starts a climb at an elevation of 380 ft. above sea level. At his first rest stop he has climbed 182 ft., and by his second rest stop he has climbed another 208 ft. It is getting late in the day, so the climber starts his way down the mountain. If the climber descends 235 ft, how much does he need to descend to return to his original starting point?(1 point) Responses
The climber started at an elevation of 380 ft above sea level. He then climbed 182 ft and another 208 ft, for a total climb of 182 + 208 = <<182+208=390>>390 ft.
Since it is getting late in the day, the climber starts to descend. He descends 235 ft.
To return to his original starting point, the climber needs to descend a total of 390 - 235 = 155 ft. Answer: \boxed{155}.