A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The Aquarium will contain 1×10^5 gallons of water. How many tetras can it house? Write the answer in scientific notation
To calculate the number of tetras that can be housed in the aquarium, we need to divide the total gallons of water by the amount of water needed for each tetra.
Number of tetras = Total gallons of water / Water needed per tetra
Number of tetras = (1×10^5 gallons) / (1.25 gallons/tetra)
To divide by a fraction, we can multiply by its reciprocal:
Number of tetras = (1×10^5 gallons) * (1/tetra ÷ 1.25 gallons)
Simplifying:
Number of tetras = 1×10^5 / 1.25
In scientific notation, dividing by 1.25 is the same as multiplying by 0.8 (1.25 = 1 / 0.8).
Number of tetras = 1×10^5 * 0.8
Multiplying the whole number by the power of 10:
Number of tetras = 8×10^4
Therefore, the aquarium can house 8 x 10^4 tetras.
To calculate the number of neon tetras that the aquarium can house, we divide the total volume of water in the aquarium by the amount of water needed for each neon tetra.
1×10^5 gallons of water / 1.25 gallons per tetra
To divide these numbers, we can subtract their exponents:
10^5 - 1 = 10^4
The answer is 10^4 tetras.
Therefore, the public aquarium can house 10,000 neon tetras.
To find the number of neon tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the volume of water needed for each neon tetra.
Step 1: Divide the total volume of water in the aquarium by the volume needed for each neon tetra:
1×10^5 / 1.25
Step 2: Simplify the division:
8×10^4 tetras
Therefore, the aquarium can house 8×10^4 neon tetras.