Rewrite the irrational square root 48−−√ as the product of an integer and another irrational square root.(1 point)
Responses
224−−√
2 start root 24 end root
412−−√
4 start root 12 end root
43–√
4 start root 3 end root
212−−√
2 start root 12 end root
To rewrite the irrational square root of 48 (√48) as the product of an integer and another irrational square root, we can simplify the expression by finding the largest perfect square that is a factor of the number inside the square root. In this case, the largest perfect square that is a factor of 48 is 16 (4^2).
So, we can rewrite the square root of 48 as the product of the square root of 16 and the square root of 3 (√16 * √3).
The square root of 16 (√16) is equal to 4, which is an integer.
Therefore, the rewritten expression of √48 is 4√3.