What is the irrational square root 63−−√ rewritten as the product of an integer and another irrational square root, in simplest form?(1 point)

The irrational square root of 63 can be rewritten as √(63) and simplified as √(9 * 7). Further simplifying, we get √(9) * √(7). The square root of 9 is an integer 3, so the expression √(63) can be rewritten as 3√(7).