What is the irrational cube root ^3√- 24, rewritten as a product of an integer and another irrational cube root? (1 point)
O - 2 ³√4
O 2 ³√3
- 2 ³√3
O 2 ³√6
The answer is - 2 ³√3.
To rewrite the irrational cube root -24 as a product of an integer and another irrational cube root, we need to find a perfect cube that divides -24.
The factors of -24 are -1, -2, -3, -4, -6, -8, -12, and -24.
Among these factors, the perfect cubes are -1, -8, and -27.
Since -8 is a perfect cube that divides -24, we can rewrite the cube root -24 as:
-8 * ³√3
So, the correct answer is: -8 * ³√3
To rewrite the irrational cube root ^3√- 24 as a product of an integer and another irrational cube root, we need to simplify the expression.
First, let's factorize -24. We can write -24 as -1 * 2^3 * 3.
Now, let's simplify the cube root. The cube root of -1 is -1, and the cube root of 2^3 is 2. Therefore, the cube root of -24 can be rewritten as:
^3√-24 = -1 * 2 * ³√3
So the correct answer is: - 2 ³√3.