Rewrite the irrational square root √48 as the product of an integer and another irrational square root.(1 point)

Responses

2√24
2 start root 24 end root

4√3
4 start root 3 end root

4√12
4 start root 12 end root

2√12

2√12

To rewrite the irrational square root √48 as the product of an integer and another irrational square root, you can look for perfect square factors of 48.

To find the perfect square factors of 48, we can use the prime factorization method.

First, let's find the prime factorization of 48:
48 = 2 * 2 * 2 * 2 * 3

We can group the 2s, giving us:
48 = (2 * 2) * (2 * 2) * 3

Simplifying further, we have:
48 = 4 * 4 * 3

Now, we can rewrite the square root of 48 as:
√48 = √(4 * 4 * 3)

Using the rule of square roots, we can rewrite it as:
√48 = √4 * √4 * √3

Simplifying, we get:
√48 = 4 * 2√3

Therefore, the irrational square root √48 can be written as the product of an integer (4) and another irrational square root (2√3).

So the correct response would be: 4√3.