Tocarre and anesia have glitter markers in a ratio of 2:3 they have a total of 30 glitter markers how many glitter markers does anesia have 6 or 12 or 18 or 24
In the given ratio 2:3, there are a total of 2 + 3 = <<2+3=5>>5 parts.
To find the value of each part, we divide the total quantity by the total number of parts: 30 / 5 = <<30/5=6>>6.
Since Anesia has 3 parts according to the ratio, the number of glitter markers she has is 3 * 6 = <<3*6=18>>18.
Therefore, Anesia has 18 glitter markers.
To find out how many glitter markers Anesia has, we need to determine the ratio of Tocarre and Anesia's markers.
Let's represent Tocarre's markers as 2x and Anesia's markers as 3x, where x is the common multiplier.
Since Tocarre and Anesia have a total of 30 markers, we can write the equation:
2x + 3x = 30
Combining like terms:
5x = 30
To solve for x, we divide both sides of the equation by 5:
x = 30/5
x = 6
Now that we know the value of x, we can find the number of glitter markers Anesia has:
Anesia's markers = 3x
Anesia's markers = 3 * 6
Anesia's markers = 18
Therefore, Anesia has 18 glitter markers.
To solve this problem, we'll use a simple algebraic approach.
First, let's assign variables to represent the number of glitter markers for Tocarre and Anesia. Let's say T represents Tocarre's markers, and A represents Anesia's markers.
We're given that the ratio of Tocarre's markers to Anesia's markers is 2:3. This means that for every 2 markers Tocarre has, Anesia has 3 markers.
We can express this relationship in the form of an equation:
T/A = 2/3
Now, we know the total number of glitter markers they have together is 30. So we can set up another equation:
T + A = 30
To solve this system of equations, we can use substitution. We'll solve the first equation for T, and then substitute it into the second equation.
From the first equation:
T/A = 2/3
Cross-multiplying gives us:
3T = 2A
Solving for T, we can divide both sides by 3:
T = 2A/3
Now, substitute this value of T into the second equation:
(2A/3) + A = 30
Combining like terms:
(5A/3) = 30
To isolate A, we can multiply both sides by 3/5:
A = 18
So, Anesia has 18 glitter markers.