Tocarre and Anesia have glitter markers in a ration of 2:3. They have a total of 30 glitter markers. How many glitter markers does Anesia have?
A 6
B 12
C 18
D 24
The ratio of Tocarre to Anesia's glitter markers is 2:3.
The total ratio is 2+3 = 5.
To find the number of Anesia's glitter markers, we divide the total number of glitter markers by the total ratio:
30 / 5 = 6
Therefore, Anesia has 6 x 3 = <<6*3=18>>18 glitter markers.
So, the answer is C) 18.
To solve this problem, we need to find out how many glitter markers Anesia has, given that the ratio between Tocarre and Anesia is 2:3 and they have a total of 30 glitter markers.
To find the number of glitter markers Anesia has, we first need to determine the total number of parts in the ratio. In this case, the total number of parts is 2 + 3 = 5.
Next, we can determine the value of each part by dividing the total number of glitter markers by the total number of parts. So, 30 / 5 = 6.
Since Anesia has three parts of the ratio, we can calculate the number of glitter markers she has by multiplying the value of each part (6) by the number of parts she has. Therefore, Anesia has 6 * 3 = 18 glitter markers.
Therefore, the correct answer is C) 18.
To find out how many markers Anesia has, we need to determine the ratio value that corresponds to her.
The ratio of Tocarre to Anesia is 2:3, meaning for every 2 markers Tocarre has, Anesia has 3 markers.
To find the value of one ratio unit, we divide the total number of markers by the sum of the ratio parts. In this case, 2 + 3 = 5.
So, 30 markers divided by 5 equals 6.
Therefore, Anesia has 3 units in the ratio, which equals 3 times 6.
Hence, Anesia has 18 glitter markers.
The correct answer is C) 18.