A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1x10^5 gallons of water. How many tetras can it house? Write the answer in scientific notation.
To find the number of tetras the aquarium can house, we need to divide the volume of water in the aquarium by the volume of water needed per tetra.
Number of tetras = (Volume of water in aquarium) / (Volume of water needed per tetra)
Number of tetras = (1x10^5 gallons) / (1.25 gallons)
Number of tetras = 8x10^4
Therefore, the aquarium can house 8x10^4 tetras.
To find out how many tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the amount of water each tetra needs.
The aquarium contains 1x10^5 gallons of water, and each neon tetra needs 1.25 gallons of water. To determine the number of tetras, we divide the total volume of water by the amount needed per tetra:
1x10^5 gallons ÷ 1.25 gallons/tetra = 8x10^4 tetras
Therefore, the aquarium can house 8x10^4 tetras in scientific notation.
To find out how many neon tetras can be housed in the aquarium, we divide the total gallons of water in the aquarium by the water requirement for each neon tetra.
Total gallons of water in the aquarium = 1 x 10^5 gallons
Water requirement for each neon tetra = 1.25 gallons
Number of tetras = Total gallons of water in the aquarium / Water requirement for each tetra
Number of tetras = (1 x 10^5) / 1.25
Now, simplify the division:
Number of tetras = 8 x 10^4
Therefore, the aquarium can house 8 x 10^4 neon tetras.