A public aquarium is being built to contain neon tetras. Each neon tetra needs of water. The aquarium will contain of water. How many tetras can it house? Write the answer in scientific notation.
To find the number of tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water needed for each individual neon tetra.
The volume of water needed for each neon tetra is given as 10^(-4) liters.
The total volume of water in the aquarium is given as 10^6 liters.
So, the number of tetras that can be housed in the aquarium is:
(10^6) / (10^(-4)) = 10^(6 + 4) = 10^10
Therefore, the aquarium can house 10^10 neon tetras.
To find the number of neon tetras that can be housed in the aquarium, we can divide the total amount of water in the aquarium by the amount of water needed per tetra.
Let's begin by converting both values to scientific notation.
The amount of water needed per tetra is .
To express it in scientific notation, we move the decimal point one place to the left. Therefore,
The amount of water needed per tetra is .
The total amount of water in the aquarium is .
To express it in scientific notation, we move the decimal point to the left until we have a number between 1 and 10.
So,
The total amount of water in the aquarium is .
Now, we can divide the total amount of water in the aquarium by the amount of water needed per tetra, keeping the exponent of 10 the same.
Therefore,
Dividing both values, we get:
Therefore, the aquarium can house neon tetras.
To find out how many tetras can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the amount of water needed for each tetra.
The total volume of water in the aquarium is 5.6 x 10^5 liters.
The amount of water needed for each tetra is 0.5 liters.
To calculate the number of tetras, we divide the total volume of water by the amount of water needed for each tetra:
(5.6 x 10^5 liters) / (0.5 liters) = 1.12 x 10^6 tetras
Therefore, the aquarium can house 1.12 x 10^6 tetras.