A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105 gallons of water. How many tetras can it house? Write the answer in scientific notation.
To determine how many neon tetras can be housed in the aquarium, divide the total amount of water in the aquarium by the amount of water each tetra needs.
Number of tetras = Total water volume / Water needed per tetra
Number of tetras = 1×105 gallons / 1.25 gallons per tetra
Number of tetras = (1×105) / (1.25)
Number of tetras = (100,000) / (1.25)
Number of tetras = 80,000
The aquarium can house 80,000 neon tetras.
Written in scientific notation, this value would be:
Number of tetras = 8 × 10^4
To determine the number of neon tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the amount of water needed per tetra.
Let's calculate that:
Number of tetras = total volume of water / water needed per tetra
Number of tetras = 1x10^5 gallons / 1.25 gallons
Number of tetras = 8x10^4
Therefore, the aquarium can house 8x10^4 neon tetras.
To calculate the number of tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the amount of water needed per neon tetra.
The total volume of water in the aquarium is given as 1×10^5 gallons.
Each neon tetra needs 1.25 gallons of water.
So, the calculation is:
Number of tetras = Total volume of water in the aquarium / Amount of water needed per tetra
Number of tetras = 1×10^5 gallons / 1.25 gallons
Now, let's simplify the calculation:
Number of tetras = (1×10^5) / (1.25)
Number of tetras = 8×10^4
Therefore, the aquarium can house 8×10^4 neon tetras.