A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105
gallons of water. How many tetras can it house? Write the answer in scientific notation.(1 point)
To find the number of tetras that can be housed, we divide the total gallons of water in the aquarium by the gallons of water each tetra needs:
1×10^5 gallons / 1.25 gallons = 8×10^4 tetras
Therefore, the aquarium can house 8×10^4 tetras.
To find out how many tetras the aquarium can house, divide the total volume of water in the aquarium by the volume of water required for each tetra.
Step 1: Volume of water needed for each tetra
Each neon tetra needs 1.25 gallons of water.
Step 2: Total volume of water in the aquarium
The aquarium contains 1x10^5 (100,000) gallons of water.
Step 3: Calculate the number of tetras the aquarium can house
Divide the total volume of water in the aquarium by the volume of water needed for each tetra:
Number of tetras = Total volume of water in the aquarium / Volume of water needed for each tetra
Number of tetras = (1x10^5 gallons) / (1.25 gallons)
Step 4: Simplify the answer to scientific notation
Number of tetras = 8x10^4
So, the aquarium can house 8x10^4 tetras.
Note: When converting the answer to scientific notation, we express the number as a decimal between 1 and 10 multiplied by a power of 10. In this case, 8 is the decimal, and 10^4 is the power of 10.
To find the number of tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water needed for each neon tetra.
The total volume of water in the aquarium is 1×10^5 gallons.
The volume of water needed for each neon tetra is 1.25 gallons.
To determine the number of neon tetras the aquarium can house, we divide the total volume of water by the volume of water needed for each tetra:
(1×10^5) / 1.25 = 8×10^4 tetras
Therefore, the aquarium can house 8×10^4 tetras.