A public aquarium is being built to contain neon tetras each neon tetra needs 1.25 gallons of water. The aquarium will contain 1x10^5 gallons of water. How many tetras can it house? Write the answer in scientific notation.
To find out how many tetras can the aquarium house, we need to divide the total volume of water in the aquarium by the volume needed for each tetra.
The aquarium has a volume of 1x10^5 gallons of water.
Each tetra needs 1.25 gallons of water.
So, the number of tetras the aquarium can house is given by:
1x10^5 gallons ÷ 1.25 gallons/tetra
Simplifying, the gallons unit cancels out, leaving only the numerical value:
1x10^5 ÷ 1.25
Calculating this, we get:
8x10^4
Therefore, the aquarium can house 8x10^4 tetras.
To find the number of neon tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water required per neon tetra.
Volume of water in aquarium = 1x10^5 gallons
Volume of water required per neon tetra = 1.25 gallons
Number of tetras = (Volume of water in aquarium) / (Volume of water required per tetra)
Number of tetras = (1x10^5 gallons) / (1.25 gallons)
Number of tetras = 8x10^4 tetras
Therefore, the aquarium can house 8x10^4 neon tetras.
To determine the number of neon tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the volume of water required for each tetra.
Let's perform the calculation step by step:
1. Calculate the number of tetras:
Number of tetras = Total volume of water / Volume of water required for each tetra
Number of tetras = 1x10^5 gallons / 1.25 gallons
2. Divide the two volumes:
Number of tetras = 8x10^4 tetras
Therefore, the aquarium can house 8x10^4 neon tetras.