A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)
Responses
0.01 N
0.01 N
1 N
1 N
6.5 N
6.5 N
7.5 N
To calculate the force exerted by the floor on the ball, we can use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = m * a.
First, we need to convert the racket's speed from kilometers per hour to meters per second. To do this, we divide the speed by 3.6 (since there are 3.6 kilometers in 1 hour):
65 km/h รท 3.6 m/s^2 = 18.06 m/s^2.
Next, we can calculate the force exerted by the tennis player's racket on the ball. Using the formula for force, F = m * a, and substituting the given values:
F = 0.1 kg * 18.06 m/s^2 = 1.806 N.
Since the ball subsequently accelerates at the same rate when it hits the floor, the force exerted by the floor on the ball is also 1.806 N.
Therefore, the correct answer is 1 N.
To find the force exerted by the floor on the south end of the court on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
First, we need to convert the mass of the tennis ball from kilograms to grams. There are 1000 grams in a kilogram, so the mass of the ball is 0.1 * 1000 = 100 grams.
Next, we need to convert the velocity of the racket from kilometers per hour to meters per second. There are 1000 meters in a kilometer and 3600 seconds in an hour, so the velocity is 65 * (1000/3600) = 18.056 meters per second.
Given that the acceleration is 10 meters per second squared, and the mass of the ball is 100 grams (0.1 kilograms), we can calculate the force using the formula F = m * a:
F = 0.1 kg * 10 m/s^2 = 1 N
Therefore, the correct answer is 1 N.
To calculate the force exerted by the floor on the south end of the court on the tennis ball, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).
Given information:
Mass of the tennis ball (m) = 0.1 kg
Acceleration (a) = 10 m/s^2
Using the formula F = m * a, we can calculate the force:
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the floor exerts a force of 1 N on the ball.