A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)
Responses
1 N
1 N
7.5 N
7.5 N
0.01 N
0.01 N
6.5 N
6.5 N
To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is the product of mass (m) and acceleration (a): F = m * a.
Given that the mass of the tennis ball is 0.1 kilograms and the acceleration of the ball is 10 meters per second squared, we can calculate the force exerted by the floor:
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the floor on the south end of the court exerts a force of 1 Newton on the ball.
To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma).
Given:
Mass of the ball (m) = 0.1 kg
Acceleration (a) = 10 m/s²
Using the given values and Newton's second law, we can calculate the force exerted by the floor on the ball:
F = ma
F = 0.1 kg × 10 m/s²
F = 1 N
Therefore, the correct answer is 1 N.
To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
First, let's convert the mass of the tennis ball from 0.1 kilograms to grams since the acceleration is given in meters per second squared.
0.1 kilograms = 100 grams
Next, we can substitute the values into the equation:
F = 100 g * 10 m/s^2
F = 1000 g * m/s^2
Now, let's convert grams to kilograms by dividing by 1000:
F = 1 kg * m/s^2
Therefore, the force exerted by the floor on the ball is 1 Newton (N).
So, the correct answer is:
1 N