A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Question

A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Responses

1 N
1 N

0.01 N
0.01 N

6.5 N
6.5 N

7.5 N

Answer 1

To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m * a

The mass of the tennis ball is 0.1 kilograms and the acceleration is 10 meters per second squared. Plugging in these values, we get:

F = 0.1 kg * 10 m/s^2
F = 1 N

Therefore, the floor on the south end of the court exerts a force of 1 N on the ball.

Answer 2

To calculate the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

Given:
Mass of the tennis ball (m) = 0.1 kg
Acceleration (a) = 10 m/s²

First, let's calculate the force exerted on the ball by the player's racket.

The initial velocity of the racket (v) is given as 65 km/h. We need to convert it to m/s:
65 km/h = (65 * 1000) / (60 * 60) = 18.1 m/s

Using the formula for force, F = m * a, we can calculate the force exerted by the racket on the ball:
Force = 0.1 kg * 18.1 m/s = 1.81 N

Now, since the ball hits the floor on the south end of the tennis court and is sent back with the same acceleration, the force exerted by the floor on the ball will also be 1.81 N.

Therefore, the correct answer is:
1.81 N

Answer 3

To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

First, let's convert the velocity of the racket from kilometers per hour to meters per second. We can do this by dividing the velocity by 3.6 because there are 3.6 seconds in an hour.

Velocity in m/s = 65 km/hr / 3.6 = 18.06 m/s

Next, we can calculate the initial velocity (u) of the ball when it leaves the racket. The initial velocity of the ball will be equal to the final velocity (which is 18.06 m/s) because it is hit directly from the racket.

Now, we can use the equation of motion v^2 = u^2 + 2as to calculate the distance (s) traveled by the ball. In this case, the final velocity (v) is 0 m/s because the ball hits the floor and comes to a stop.

0 = (18.06 m/s)^2 + 2 * (-10 m/s^2) * s

Simplifying the equation, we get:

0 = 326.83 m^2/s^2 - 20 m/s^2 * s

20 m/s^2 * s = 326.83 m^2/s^2

s = 16.34 meters

Therefore, the ball travels a distance of 16.34 meters from the north end to the south end of the tennis court.

Now, we can calculate the force exerted by the floor on the ball using Newton's second law of motion.

Force = mass * acceleration

Since the mass of the ball is given as 0.1 kg and the acceleration is given as 10 m/s^2, we have:

Force = 0.1 kg * 10 m/s^2 = 1 N

So, the floor on the south end of the court exerts a force of 1 Newton on the ball. Therefore, the correct answer is: 1 N.