A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)%0D%0AResponses%0D%0A%0D%0A1 N%0D%0A1 N%0D%0A%0D%0A6.5 N%0D%0A6.5 N%0D%0A%0D%0A0.01 N%0D%0A0.01 N%0D%0A%0D%0A7.5 N
To find the force exerted by the floor on the ball, we can use Newton's second law of motion:
Force (F) = mass (m) * acceleration (a)
Given:
mass of the ball (m) = 0.1 kg
acceleration (a) = 10 m/s^2
Plugging in the values, we get:
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the force exerted by the floor on the ball is 1 N.
To determine the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the tennis ball (m) = 0.1 kg
Acceleration (a) = 10 m/s^2
First, we need to find the acceleration due to gravity when the ball hits the floor on the south end of the court. Assuming no other forces are acting on the ball, the acceleration due to gravity is 9.8 m/s^2.
Next, let's find the force exerted by the floor on the ball. Using Newton's second law, we have:
F = m * a
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the force exerted by the floor on the south end of the court on the tennis ball is 1 N.
So, the correct answer is 1 N.
To calculate the force exerted by the floor on the tennis ball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F=ma).
First, let's find the acceleration of the ball. We know that the ball accelerated at a rate of 10 meters per second squared, which means its acceleration is 10 m/s².
Next, let's find the mass of the tennis ball. We are given that the ball weighs 0.1 kilograms.
Now we can substitute the values into the formula F=ma.
F = (0.1 kg) × (10 m/s²)
F = 1 N
Therefore, the floor on the south end of the court exerted a force of 1 Newton on the tennis ball.
So the correct answer is 1 N.