A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point) Responses The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is negative 10.48 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is negative 19.05 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second. The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.

The correct response is: The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.

The correct answer is:

The quotient that describes the rate of change in the squirrel’s height above the ground is negative 19.05 feet/second.

To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the change in time.

The squirrel starts on a perch 100 feet above the ground and moves to its stored acorns 45 feet from the ground. So, the change in height is 100 - 45 = 55 feet.

The squirrel takes 5.25 seconds to make this change in height.

Now, divide the change in height (55 feet) by the change in time (5.25 seconds):

55 feet / 5.25 seconds = 10.48 feet/second

Since the squirrel is moving to a lower height, the rate of change is negative. Therefore, the correct interpretation is:

The quotient that describes the rate of change in the squirrel's height above the ground is -10.48 feet/second.