A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth.
To find the rate of change in the squirrel's height above the ground, we need to calculate the difference in height and divide it by the time it takes for the squirrel to change its height.
The initial height of the squirrel is 100 feet above the ground.
The final height of the squirrel is 45 feet above the ground.
Therefore, the difference in height is 100 - 45 = 55 feet.
The time it takes for the squirrel to change its height is 5.25 seconds.
To calculate the rate of change, we divide the difference in height by the time it takes, which is 55/5.25 = 10.48 feet per second.
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet per second.
To describe the rate of change in the squirrel's height above the ground, we can divide the change in height by the time it takes for the squirrel to move. In this case, the squirrel moves from the perch at 100 feet above the ground to its stored acorns in a hole that is 45 feet from the ground in 5.25 seconds.
The change in height is given by 100 feet - 45 feet = 55 feet.
To find the rate of change, we divide the change in height by the time it takes: 55 feet / 5.25 seconds ≈ 10.48 feet per second.
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet per second.
To find the rate of change in the squirrel's height above the ground, we need to calculate how much the squirrel's height decreases in 5.25 seconds.
Given that the squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns, we can subtract the distance the squirrel moves from its initial height to its final height.
The distance moved by the squirrel is equivalent to the height of the tree minus the height of the stored acorns. So, the distance moved by the squirrel is 45 feet.
Therefore, the rate of change in the squirrel's height above the ground can be calculated as the distance moved divided by the time taken. In this case, it is 45 feet / 5.25 seconds.
To find the quotient, divide 45 by 5.25:
45 / 5.25 = 8.57.
Rounding the answer to the nearest hundredth, the rate of change in the squirrel's height above the ground is approximately 8.57 feet per second.